Question

During Gibson Assembly, what specific structural feature at the 3&#x27; and 5&#x27; ends of overlapping DNA fragments allows the T5 exonuclease to reveal the single-stranded complementary regions?

Accepted Answer

The structural feature that allows T5 exonuclease to function is the presence of double-stranded DNA ends with overlapping terminal sequences. Gibson Assembly uses fragments that have identical sequences at their 5&#x27; and 3&#x27; ends, which act as points of homology. T5 exonuclease is an enzyme that specifically removes nucleotides from the 5&#x27; ends of double-stranded DNA molecules. Because the enzyme chews back the 5&#x27; strands, it progressively exposes the single-stranded 3&#x27; tails. These newly exposed, single-stranded regions are complementary to the tails on the adjacent DNA fragment. Once these sequences are revealed, they naturally base-pair with each other through hydrogen bonding between complementary bases. This base pairing aligns the fragments, allowing a DNA polymerase to fill in any remaining gaps and a DNA ligase to seal the nicks in the sugar-phosphate backbone, resulting in a continuous, double-stranded DNA molecule.

During Gibson Assembly, what specific structural feature at the 3' and 5' ends of overlapping DNA fragments allows the T5 exonuclease to reveal the single-stranded complementary regions?

The structural feature that allows T5 exonuclease to function is the presence of double-stranded DNA ends with overlapping terminal sequences. Gibson Assembly uses fragments that have identical sequences at their 5' and 3' ends, which act as points of homology. T5 exonuclease is ....

Community Answers

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During Gibson Assembly, what specific structural feature at the 3' and 5' ends of overlapping DNA fragments allows the T5 exonuclease to reveal the single-stranded complementary regions?

The structural feature that allows T5 exonuclease to function is the presence of double-stranded DNA ends with overlapping terminal sequences. Gibson Assembly uses fragments that have identical sequences at their 5' and 3' ends, which act as points of homology. T5 exonuclease is ....

Community Answers